Home
Class 12
PHYSICS
The interference pattern is obtained wit...

The interference pattern is obtained with two coherent light sources of intensity ration n. In the interference pattern, the ratio
`(I_(max)-I_(min))/(I_(max)+I_(min))` will be

A

`sqrt(n)/(n+1)`

B

`(2sqrt(n))/(n+1)`

C

`sqrt(n)/((n+1)^(2))`

D

`(2sqrt(n))/((n+1)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

It is given that, `I_(2)/I_(1)=nrArrI_(2)=nI_(1)`
`:.` Ratio of intensities is given by
`(I_(max)-I_(min))/(I_(max)+I_(min))=((sqrtI_(2)+sqrt(I_(1)))^(2)-(sqrt(I_(2)-I_(1)))^(2))/((sqrt(I_(1))+sqrt(I_(2)))^(2)+(sqrt(I_(2))-sqrt(I_(1)))^(2))`
`=((sqrt(I_(2)/I_(1))+1)^(2)-(sqrt(I_(2)/I_(1))-1)^(2))/((sqrt(I_(2)/I_(1))+1)^(2)+(sqrt(I_(2)/I_(1))-1)^(2))`
`=((sqrt(n)+1)^(2)-(sqrt(n)-1)^(2))/((sqrt(n)+1)^(2)+(sqrt(n)-1)^(2))=(2sqrt(n))/(n+1)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WAVE OPTICS

    DC PANDEY|Exercise For JEE main (Only one option is Correct )|22 Videos
  • WAVE OPTICS

    DC PANDEY|Exercise For JEE Advanced Only one option is correct|23 Videos
  • WAVE OPTICS

    DC PANDEY|Exercise match column|4 Videos
  • SOLVED PAPERS 2018

    DC PANDEY|Exercise JIPMER|22 Videos

Similar Questions

Explore conceptually related problems

Two coherent sources of intensity ratio beta interfere. Then the value of (I_(max)-I_(min))(I_(max)+I_(min)) is

Two coherent light sources having intensity in the ratio 2x produce an interference pattern. The ratio (I_(max)-I_(min))/(I_(max)+I_(min)) will be :

Knowledge Check

  • The interference pattern is obtained with two coherent light sources of intensity ratio n. In the interference patten, the ratio (I_(max)-I_(min))/(I_(max)+I_(min)) will be

    A
    (a) `(sqrtn)/((n+1)^2)`
    B
    (b) `(2sqrtn)/((n+1)^2)`
    C
    (c) `(sqrtn)/(n+1)`
    D
    (d) `(2sqrtn)/(n+1)`
  • The interference pattern is obtained with two coherent light sources of intensity ratio n. In the interference pattern, the ratio (I_("max" - I_("min"))/(I_("max") + I_("min"))) will be :

    A
    `(sqrt(n))/((n+1)^(2))`
    B
    `(2sqrt(n))/((n+1)^(2))`
    C
    `(sqrt(n))/(n+1)`
    D
    `(2sqrt(n))/(n+1)`
  • The interference pattern is obtained with two coherent light sources of intensity ratio n. In the interference pattern, the ratio (I_("max" - I_("min")))/(I_("max") + I_("min")) will be :

    A
    `(sqrt(n))/((n+1)^(2))`
    B
    `(2sqrt(n))/((n+1)^(2))`
    C
    `(sqrt(n))/(n+1)`
    D
    `(2sqrt(n))/(n+1)`
  • Similar Questions

    Explore conceptually related problems

    Two coherent sources of intensity ratio alpha interfere. In interference pattern (I_(max)-I_("min"))/(I_(max)-I_("min")) =

    Two coherent sources of intensity ratio alpha interface . In interference pattern (I_("max") - I_("min"))/(I_("max") + I_("min")) =

    Two doherent sources of intensity ratio alpha interfere in interference pattern (I_(max)-I_(min))/(I_(max)+I_(min)) is equal to

    Two coherent sources of intensity ratio beta^2 interfere. Then, the value of (I_(max)- I_(min))//(I_(max)+I_(min)) is

    Two coherent sources with intensity ratio alpha interfere. Then, the ratio (l_(max)-l_("min"))/(l_(max)+l_("min")) is