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A manufacturer has 600 liters of 12% sol...

A manufacturer has 600 liters of 12% solution of acid. How many litres of a 30% acid solution must be added to it so that the acid content in the resulting mixture will be more then 15% but less than 18%?

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To solve the problem step by step, we need to determine how many liters of a 30% acid solution must be added to 600 liters of a 12% acid solution so that the resulting mixture has an acid content that is more than 15% but less than 18%. ### Step 1: Define the Variables Let \( x \) be the number of liters of the 30% acid solution that we need to add. ### Step 2: Calculate the Total Volume of the Mixture The total volume of the mixture after adding \( x \) liters of the 30% solution will be: \[ 600 + x \text{ liters} \] ### Step 3: Calculate the Acid Content in the Mixture The acid content from the 12% solution is: \[ \text{Acid from 12% solution} = 12\% \text{ of } 600 = \frac{12}{100} \times 600 = 72 \text{ liters} \] The acid content from the 30% solution is: \[ \text{Acid from 30% solution} = 30\% \text{ of } x = \frac{30}{100} \times x = 0.3x \text{ liters} \] Thus, the total acid content in the mixture is: \[ \text{Total acid} = 72 + 0.3x \text{ liters} \] ### Step 4: Set Up the Inequalities We want the acid content to be more than 15% and less than 18% of the total mixture. This gives us two inequalities: 1. More than 15%: \[ \frac{72 + 0.3x}{600 + x} > 0.15 \] 2. Less than 18%: \[ \frac{72 + 0.3x}{600 + x} < 0.18 \] ### Step 5: Solve the First Inequality Starting with the first inequality: \[ 72 + 0.3x > 0.15(600 + x) \] Expanding the right side: \[ 72 + 0.3x > 90 + 0.15x \] Rearranging gives: \[ 72 - 90 > 0.15x - 0.3x \] \[ -18 > -0.15x \] Dividing by -0.15 (and flipping the inequality): \[ x > 120 \] ### Step 6: Solve the Second Inequality Now, we solve the second inequality: \[ 72 + 0.3x < 0.18(600 + x) \] Expanding the right side: \[ 72 + 0.3x < 108 + 0.18x \] Rearranging gives: \[ 72 - 108 < 0.18x - 0.3x \] \[ -36 < -0.12x \] Dividing by -0.12 (and flipping the inequality): \[ x < 300 \] ### Step 7: Combine the Results From the two inequalities, we have: \[ 120 < x < 300 \] ### Conclusion The manufacturer must add more than 120 liters but less than 300 liters of the 30% acid solution.

To solve the problem step by step, we need to determine how many liters of a 30% acid solution must be added to 600 liters of a 12% acid solution so that the resulting mixture has an acid content that is more than 15% but less than 18%. ### Step 1: Define the Variables Let \( x \) be the number of liters of the 30% acid solution that we need to add. ### Step 2: Calculate the Total Volume of the Mixture The total volume of the mixture after adding \( x \) liters of the 30% solution will be: \[ ...
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Knowledge Check

  • A manufacturer has 600L of 12% solution of acid the volume of 30% acid solution must be added to it so that acid content in the resulting mixture will be more than 15% but less than 18% is between….X… and ….Y… here X and Y refer to

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    B
    120L and 300L
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    60L and 200L
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    20litres
    C
    36litres
    D
    None of these
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    1000ml
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    300ml
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