Home
Class 12
MATHS
The distance covered by a particle movin...

The distance covered by a particle moving in a straight line from a fixed point on the line is `s ,` where `s^2=a t^2+2b t+cdot` Then prove that acceleration is proportional to `s^(-3)dot`

Answer

Step by step text solution for The distance covered by a particle moving in a straight line from a fixed point on the line is s , where s^2=a t^2+2b t+cdot Then prove that acceleration is proportional to s^(-3)dot by MATHS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

A particle is moving in a straight line is at a distance S from a point O on the line in time t, where S=t^3-6t^2+8t+5 .Find the velocity when the acceleration is 12 cm//sec^2 .

The distance traversed by a particle moving along a straight line is given by x = 180 t + 50 t^(2) metre. Find the velocity at the end of 4s.

Knowledge Check

  • If the velocity v of a particle moving along a straight line and its distance s from a fixed point on the line are related by v^(2)=a^(2)+s^(2) , then its acceleration equals

    A
    as
    B
    s
    C
    `s^(2)`
    D
    2s

  • A particle moves in a straight line so that s = sqrt t , then its acceleration is proportional to :

    A
    `(velocity)^3`
    B
    velocity
    C
    `(velocity)^2`
    D
    `(velocity)^3//2`

  • A particle moves in a straight line so that s = sqrt t , then its acceleration is proportional to :

    A
    `(velocity)^3`
    B
    velocity
    C
    `(velocity)^2`
    D
    `(velocity)^3//2`

    • Similar Questions

    Explore conceptually related problems

    If a particle moving in a straight line and its distance x cms from a fixed point O on the line is given by x=sqrt(1+t^(2)) cms, then acceleration of the particle at t sec. is

    A particle is moving on a straight line and its distance x cms from a fixed point O on the line is given by x=sqrt(t^(2)+1) then the velocity of particle at t=1 is

    A particle moves in a straight line so that s=sqrt(t) , then its acceleration is proportional to

    The distance s travelled by a particle moving on a straight line in time t sec is given by s=2t^(3)-9t^(2)+12t+6 then the initial velocity of the particle is

    The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

    Home
    Profile