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The torque on a planet about the cent...

The torque on a planet about the centre of sun is

A

Zero

B

Negative

C

Positive

D

Depend on mass of planet

Text Solution

AI Generated Solution

The correct Answer is:
To find the torque on a planet about the center of the Sun, we can follow these steps: ### Step 1: Understand the Definition of Torque Torque (τ) is defined as the cross product of the position vector (r) and the force vector (F). Mathematically, it is given by: \[ \tau = \mathbf{r} \times \mathbf{F} \] This can also be expressed in terms of the magnitudes of the vectors and the angle (θ) between them: \[ \tau = rF \sin(\theta) \] ### Step 2: Identify the Position and Force Vectors - The position vector (r) points from the center of the Sun to the planet. - The gravitational force (F) acting on the planet due to the Sun is directed towards the center of the Sun. ### Step 3: Determine the Angle Between the Vectors Since the force vector (F) is directed towards the Sun, and the position vector (r) points away from the Sun, the angle (θ) between these two vectors is 180 degrees. ### Step 4: Calculate the Sine of the Angle Using the sine function: \[ \sin(180^\circ) = 0 \] ### Step 5: Substitute into the Torque Formula Substituting the values into the torque formula: \[ \tau = rF \sin(180^\circ) = rF \cdot 0 = 0 \] ### Conclusion The torque on a planet about the center of the Sun is zero. ### Final Answer \[ \text{The torque on a planet about the center of the Sun is } 0. \] ---
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Knowledge Check

  • A: The speed of a planet is maximum at perihelion . R : The angular momentum of a planet about centre of sun is conserved .

    A
    If both Assertion & Reason are true . And the reason is the correct explanation of the assertion , then mark (1)
    B
    If both Assertion & Reason are true but the reason is not the correct explanation of the assertion , then mark (2)
    C
    If Assertion is true statement but Reason is false , then mark (3)
    D
    It will move the same speed , tangentially to the spacecraft
  • The period of revolution of a planet about the sun is T. If a is radius of the circular orbit, then what is true?

    A
    `T alpha a`
    B
    `T alpha a^(2)`
    C
    `T^(2) alpha a^(3)`
    D
    `T^(3) alpha a^(2)`
  • Assertion : In planetary motion angular momentum of planet about centre of sun remains constant. But linear momentum of system does not remain constant. Reason : Net torque on planet any point is zero.

    A
    If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.
    B
    If both Assertion and Reason are true but Reason is not the correct explantion of Assertion.
    C
    If Assertion is true, but the Reason is false.
    D
    If Assertion is false but the Reason is true.
  • Similar Questions

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    The rate of change of angular momentum of a system of particles about the centre of mass is equal to the sum of external torque about the centre of mass when the centre of mass is :

    The time of revolution of planet A round the sun is 8 times that of another planet B . The distance of planet A from the sun is how many B from the sun

    A planet of mass m moves along an ellipse around the sun so that its maximum and minimum distance from the sun are equal to r_(1) and r_(2) respectively. Find the angular momentum of this planet relative to the centre of the sun. mass of the sun is M .

    Assertion : Areal velocity of a planet around of surface area and density is same for two planets, escape velocities will be same for both Reason : Areal velocity = (L)/(2m) , Where L is angular momentum of planet about centre of sun.

    The period of revolution of a planet around the sun is 8 times that of the earth. If the mean distance of that planet from the sun is r, then mean distance of earth from the sun is