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de-Broglie wavelength associated with an...

de-Broglie wavelength associated with an electron revolving in the ` n^(th) ` state of hydrogen atom is directily proportional to

A

n

B

`1/n`

C

`n^(2)`

D

`(1)/(n^(2))`

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To solve the question regarding the de-Broglie wavelength associated with an electron revolving in the nth state of a hydrogen atom, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Energy of the Electron:** The energy of an electron in the nth orbit of a hydrogen atom is given by the formula: \[ E_n \propto -\frac{1}{n^2} \] This indicates that the energy is inversely proportional to the square of the principal quantum number \( n \). 2. **Relating Energy to Kinetic Energy:** The kinetic energy (K.E) of the electron can be expressed as: \[ K.E = \frac{1}{2} mv^2 \] where \( m \) is the mass of the electron and \( v \) is its velocity. Since the total energy is primarily kinetic in the case of an electron in a stable orbit, we can relate the kinetic energy to the momentum \( p \). 3. **Momentum and Kinetic Energy:** The momentum \( p \) of the electron is given by: \[ p = mv \] We can also express kinetic energy in terms of momentum: \[ K.E = \frac{p^2}{2m} \] From the energy relation, we have: \[ \frac{p^2}{2m} \propto -\frac{1}{n^2} \] Thus, we can say: \[ p^2 \propto \frac{1}{n^2} \] Therefore, the momentum \( p \) is directly proportional to: \[ p \propto \frac{1}{n} \] 4. **Applying de-Broglie Wavelength Formula:** The de-Broglie wavelength \( \lambda \) is given by the formula: \[ \lambda = \frac{h}{p} \] where \( h \) is Planck's constant. Since we found that \( p \propto \frac{1}{n} \), we can substitute this into the de-Broglie wavelength formula: \[ \lambda \propto \frac{h}{p} \propto \frac{h}{\frac{1}{n}} = h \cdot n \] 5. **Conclusion:** Thus, we conclude that the de-Broglie wavelength \( \lambda \) associated with an electron revolving in the nth state of a hydrogen atom is directly proportional to \( n \): \[ \lambda \propto n \] ### Final Answer: The de-Broglie wavelength associated with an electron revolving in the nth state of a hydrogen atom is directly proportional to \( n \). ---
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Knowledge Check

  • The de Broglie wavelength associated with particle is

    A
    inversely proportional to its momentum
    B
    inversely proportional to its energy
    C
    directly proportional to its velocity
    D
    directly proportional to its momentum
  • Minimum de-Broglie wavelength is associated with

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  • Minimum de-Broglie wavelength is associated with.

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    Electron
    B
    Proton
    C
    `CO_2` molecule
    D
    `SO_2` molecule
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