de-Broglie wavelength associated with an electron revolving in the ` n^(th) ` state of hydrogen atom is directily proportional to
A
n
B
`1/n`
C
`n^(2)`
D
`(1)/(n^(2))`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the question regarding the de-Broglie wavelength associated with an electron revolving in the nth state of a hydrogen atom, we can follow these steps:
### Step-by-Step Solution:
1. **Understanding the Energy of the Electron:**
The energy of an electron in the nth orbit of a hydrogen atom is given by the formula:
\[
E_n \propto -\frac{1}{n^2}
\]
This indicates that the energy is inversely proportional to the square of the principal quantum number \( n \).
2. **Relating Energy to Kinetic Energy:**
The kinetic energy (K.E) of the electron can be expressed as:
\[
K.E = \frac{1}{2} mv^2
\]
where \( m \) is the mass of the electron and \( v \) is its velocity. Since the total energy is primarily kinetic in the case of an electron in a stable orbit, we can relate the kinetic energy to the momentum \( p \).
3. **Momentum and Kinetic Energy:**
The momentum \( p \) of the electron is given by:
\[
p = mv
\]
We can also express kinetic energy in terms of momentum:
\[
K.E = \frac{p^2}{2m}
\]
From the energy relation, we have:
\[
\frac{p^2}{2m} \propto -\frac{1}{n^2}
\]
Thus, we can say:
\[
p^2 \propto \frac{1}{n^2}
\]
Therefore, the momentum \( p \) is directly proportional to:
\[
p \propto \frac{1}{n}
\]
4. **Applying de-Broglie Wavelength Formula:**
The de-Broglie wavelength \( \lambda \) is given by the formula:
\[
\lambda = \frac{h}{p}
\]
where \( h \) is Planck's constant. Since we found that \( p \propto \frac{1}{n} \), we can substitute this into the de-Broglie wavelength formula:
\[
\lambda \propto \frac{h}{p} \propto \frac{h}{\frac{1}{n}} = h \cdot n
\]
5. **Conclusion:**
Thus, we conclude that the de-Broglie wavelength \( \lambda \) associated with an electron revolving in the nth state of a hydrogen atom is directly proportional to \( n \):
\[
\lambda \propto n
\]
### Final Answer:
The de-Broglie wavelength associated with an electron revolving in the nth state of a hydrogen atom is directly proportional to \( n \).
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