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Radioactive material 'A' has decay const...

Radioactive material 'A' has decay constant `'8 lamda'` and material 'B' has decay constant 'lamda'. Initial they have same number of nuclei. After what time, the ratio of number of nuclei of material 'B' to that 'A' will be `(1)/( e)` ?

A

`1/(lambda)`

B

`1/(7 lambda)`

C

`1/(8lambda)`

D

`1/(9lambda)`

Text Solution

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The correct Answer is:
B
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Two radioactive materials X_1 and X_2 have decay constants 10 lamda and lamda respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of X_1 to that of X_2 will be 1//e after a time.

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Knowledge Check

  • Two radioactive materials X_1 and X_2 have decay constants 10 lambda and lambda respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of X_1 to that of X_2 will be 1/e after a time

    A
    `1/(10lambda)`
    B
    `1/(11lambda)`
    C
    `11/(10lambda)`
    D
    `1/(9lambda)`

  • Two radioactive materials X_1 and X_2 have decay constants 10 lamda and lamda respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of X_1 to that of X_2 will be 1//e after a time.

    A
    `lamda`
    B
    `(1)/(2) lamda`
    C
    `(1)/(4 lamda)`
    D
    `( e)/(lamda)`

  • Two redioactive materials X_(1)andX_(2) have decay constants 10lamdaandlamda , respecitvely. If initially they have the same number of nuclei, then the ratio of the number of nuclei of X_(1) to that of X_(2) will be 1/e after a time

    A
    `(1)/((10lamda))`
    B
    `((1)/(11lamda))`
    C
    `(11)/((10lamda))`
    D
    `(1)/((9lamda))`
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