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A stone falls freely from rest and the t...

A stone falls freely from rest and the total distance covered by it in last second of its motion equals the distance covered by it in the first 3s of its motion. How long the stone will remain in the air?

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To solve the problem, we need to find the total time the stone remains in the air when the distance covered in the last second of its motion is equal to the distance covered in the first 3 seconds of its motion. ### Step-by-Step Solution: 1. **Understanding the Problem**: - The stone falls freely from rest, meaning its initial velocity (u) is 0. - We need to find the total time (t) the stone is in the air. ...
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Knowledge Check

  • A stone falls frecly from rest and the total distance covered by it in the last second of its motion cquals the distance covered by it in the first three seconds of its motion. The stone remains in the air for

    A
    6s
    B
    5s
    C
    7s
    D
    4s

  • A stone falls freely such that the distance covered by it in the last second of its motion is equal to the distance covered by it in the first 5 seconds. It remained in air for :-

    A
    12s
    B
    13s
    C
    25s
    D
    26s

  • A stone falls freely rest. The distance covered by it in the last second is equal to the distance covered by it in the first 2 s. The time taken by the stone to reach the ground is

    A
    `2.5 s`
    B
    `3.5 s`
    C
    `4 s`
    D
    `5 s`

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