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A satellite revolves round a planet in a...

A satellite revolves round a planet in an elliptical orbit. Its maximum and minimum distance from planet are `1.5xx10^(7)` metre and `0.5xx10^(7)` metre respectively. If the speed of the satellite at the farthest point is `5xx10^(3)m//s`. Calculate the speed at the nearest point.

Text Solution

Verified by Experts

The angular momentum of the satellite about the planet is constant.

`thereforemv_(1)r_(1)=mv_(2)r_(2)`
(or) `v_(1)r_(1)=v_(2)r_(2)`
`therefore` Speed at nearest part
`v_(1)=(v_(2)r_(2))/(r_1)=(5xx10^(3)xx1.5xx10^(7))/(0.5xx10^(7))`
`therefore" "v_(1)=1.5xx10^(4)m//s`
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Knowledge Check

  • The length of breadth of a rectangular plot are 5xx10^5 and 4xx10^4 metres respectively. Its area is _____

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    `9xx10^1 m^2`
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    `9xx10^9 m^2`
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    `20xx10^20 m^2`
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    20
    B
    `0.2 xx 10^(-1)`
    C
    0.05
    D
    None of these
  • If K_b and K_f for a reversible reactions are 0.8xx10^(-5) and 1.6xx10^(-4) respectively , the value of the equilibrium constant is ………………. .

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