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Two mole of ideal diatomic gas `(C_("v,m")=5//2R)` at 300 K and 5 atm expanded irreversly & adiabatically to a final pressure of 2 atm against a constant pressure of 1 atm. Calculate q, w, `DeltaH&DeltaU`.

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The correct Answer is:
`DeltaU = w = - 1247.1 ; DeltaH = - 1745.94J`

` w =nC_(V) (T_(2)- T_(1)) =- P_("ext")[(nRT_(2))/(P_(2))(nRT_(1))/(P_(1))]`
`T_(2) = 370 K`
`w= nC_(V) (T_(2)- T_(1)) =- 1247.1 J`
`q=0`
`DeltaU = w`
`DeltaH = DeltaU + nRDeltaT =- 1745.94J`
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