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The enthy change for the reaction of 5...

The enthy change for the reaction of 50 ml of ethylene with 50. 0 ml of ` H_(2)` at 1.5 atm pressure is `DeltaH =- 0.31 KJ `. What is the `DeltaU` ?

Text Solution

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The correct Answer is:
`-0.3024 kJ`
`C_(2)H_(4)" "+" "H_(2) " " to " "C_(2)H_(6)`
`50 ml " "50ml" "50ml`
`DeltaV = - 50 ml`
`W = - 1.5 (-50) xx 10^(-3) 75 atm - L= 7575 J``DeltaU = q+w`
` = - 0.3024 kJ`
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The enthalpy change for the reaction of 50 ml of ethylene with 50.0 ml of H_(2) at 1.5 atm pressure is DeltaH=-0.31KJ . What is the DeltaE .

The enthaly change for the reaction C_(2) H_(4((g))) + H_(2_((g))) to C_(2) H_(6_((g))) is - 620 J when 100 mL of ethylene and 100 mL of H_(2) react at 1 atm pressure .Calculate the pressure volume work and DeltaU .

Knowledge Check

  • The enhtaply change for the reaction of 50ml of ethylene with 50.0 mL if H_(2) at 1.5 atm pressure is DeltaH=-0.31 KJ . What is the DeltaE ?

    A
    `-0.3024`
    B
    `0.6048`
    C
    `0.1.2`
    D
    None

  • The enthalpy change for the reaction of 50.00 ml of ethylene with 50.00 ml of H_(2) at 1.5 atm pressure is DeltaH=-0.31 kJ The value of DeltaE will be

    A
    `-0.3024` kJ
    B
    0.3024 kJ
    C
    2.567 kJ
    D
    `-0.0076` kJ

  • The enthalpy change for the reaction of 5 litre of ethylene with 5 litre of H_(2) gas at 1.5 atm pressure is Delta H= -0.5 kJ . The value of Delta U will be: ( 1 atm Lt=100 J)

    A
    `-1.25 kJ`
    B
    `+1.25 kJ`
    C
    `0.25 kJ`
    D
    `-0.25 kJ`

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