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G = 6.67 xx 10^(-11) kg^(-1) m^(3) s^(-2...

`G = 6.67 xx 10^(-11) kg^(-1) m^(3) s^(-2)`. Convert it into CGS system.

A

`6.67 xx 10^(-8)g^(-1) cm^(3) s^(-2)`

B

`6.67 xx 10^(2) g^(-1) cm^(3) s^(-2)`

C

`0.149 xx 10^(-2) g^(-1) cm^(3) s^(-2)`

D

`0.149 xx 10^(2) g^(-1) cm^(3) s^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`[G] = M^(-1) L^(3)T^(-2)`
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The value of gravitation is G = 6.67 xx 10^(-11)N-m^(2)/kg^(2) in SL units . Convert it into CGS system of units .

If the value of universal gravitational constant is 6.67xx10^(11) Nm^2 kg^(-2), then find its value in CGS system.

Knowledge Check

  • The value fo universal gravitationla constant G in CGS system is 6.67xx10^(-8) dyne cm^(2) g^(-2) . Its value in SI system is

    A
    `6.67xx10^(-11) Nm^(2) kg^(-2)`
    B
    `6.67xx10^(-5) Nm^(2) kg^(-2)`
    C
    `6.67xx10^(-10) Nm^(2) kg^(-2)`
    D
    `6.67xx10^(-9) Nm^(2) kg^(-2)`

  • The value of universal gravitational constant G = 6.67 xx 10^(-11) N m^(2) kg^(-2) . The value of G in units of g^(-1) cm (^(3)s^(-2) is

    A
    `6.67 xx 10^(-8)`
    B
    `6.67 xx 10^(-7)`
    C
    `6.67 xx 10^(-9)`
    D
    `6.67 xx 10^(10)`

  • If in a system the force of attraction between two point masses of 1kg each situated 1km apart is taken as a unit force and is called notwen (newton written in reverse order) If G = 6.67 xx 10^(-11) N-m^(2)kg^(-2) in \SI units, the relation of newton and nowton is

    A
    `1 "notwen" = 6.67xx 10^(-11) "newton"`
    B
    `1 "newton" = 6.67xx 10^(-17) "notwen"`
    C
    `1 "notwen" = 6.67xx 10^(-17) "newton"`
    D
    `1 "newton" = 6.67xx 10^(-12) "notwen"`

    • Similar Questions

    Explore conceptually related problems

    The mass of the earth is 6 xx 10^(24) kg . The constant of gravitation G = 6.67 xx 10^(-11) "N-m"^(-2) kg^(-2) . The potential energy of the earth and moon system is -7.79 xx 10^(28) J . Determine the mean distance between earth and moon.

    Convert G=6.67xx10^(-11)Nm^(2)kg^(-2) to cm^(3)s^(-2)g^(-1) , where G is the universal gravitational constant.

    The radius of the earth is 6.37 xx 10^(6) m and its mean density is 5.5 xx 10^(3) "kg m"^(-3) and G = 6.67 xx 10^(-11) "N-m"^(2) kg^(-2) Find the gravitational potential on the surface of the earth.

    (a) Density of water in CGS system is g//cm^(3) . Convert it into SI unit. (b) Young's modulus of steel is 2 xx 10^(11) N//m^(2) ( SI unit). Convert in into CGS unit (in "dyne"//cm^(2) ).

    On Earth value of G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) . What is its value on Moon, where g is nearly one-sixth than that of Earth?

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