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The two blocks, m= 10 kg and M = 50 kg a...

The two blocks, m= 10 kg and M = 50 kg are free to move as shown. The coefficient of static friction between the blocks is 0.5 and there is no friction between M and the ground. A minimum horizontal force F is applied to hold m against M that is equal to -

A

100 N

B

50 N

C

240 N

D

180 N

Text Solution

Verified by Experts

Limiting condition for m to not slip in vertical downward direction, `mg-muN`
`rArrN=(mg)/(mu)=(100)/(0.5)=200N`
Same normal force would accelerate M, thus
`a_(M)=(200)/(50)=4m//s^(2)` Taking m+M as system
`F=(m+M).4=240N`
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Knowledge Check

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