0.70 g of an organic compund when dissolved in 32g of acetone produces in an elevation in boiling point of `0.25^(@)C`. Calculate the molecular mass of the organic compound. `(K_(b)" for acetone "=1.72 K kg mol^(-1))`.
Text Solution
AI Generated Solution
To solve the problem of calculating the molecular mass of the organic compound, we can follow these steps:
### Step 1: Identify the given values
- Mass of the organic compound (Wb) = 0.70 g
- Mass of the solvent (acetone) (Wa) = 32 g = 0.032 kg (conversion from grams to kilograms)
- Elevation in boiling point (ΔTb) = 0.25 °C
- Boiling point elevation constant for acetone (Kb) = 1.72 K kg mol⁻¹
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Knowledge Check
The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_b , for benzene is 2.53 K kg mol^(-1) .
A
`58 g mol^(-1)`
B
`85 g mol^(-1)`
C
`93 g mol^(-1)`
D
`108 g mol^(-1)`
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The boiling a point of benzene is 353.23K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_(b) for benzene is 2.53 K kg mol^(-1) .
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