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Home
Class 12
CHEMISTRY
0.70 g of an organic compund when dissol...

0.70 g of an organic compund when dissolved in 32g of acetone produces in an elevation in boiling point of `0.25^(@)C`. Calculate the molecular mass of the organic compound. `(K_(b)" for acetone "=1.72 K kg mol^(-1))`.

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Text Solution

AI Generated Solution

To solve the problem of calculating the molecular mass of the organic compound, we can follow these steps: ### Step 1: Identify the given values - Mass of the organic compound (Wb) = 0.70 g - Mass of the solvent (acetone) (Wa) = 32 g = 0.032 kg (conversion from grams to kilograms) - Elevation in boiling point (ΔTb) = 0.25 °C - Boiling point elevation constant for acetone (Kb) = 1.72 K kg mol⁻¹ ...
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When 1.0 g of a non-volatie solute was dissolved in 10 g benzene, elevation in boiling point temperature was found to be 1^(@)C . Calculate the molar mass of the dissoved substance. (K_(b) "for benzene = 2.53 K kg" mol^(-1)) .

The boiling point of pure acetone is 56.38^(@)C . When 0.707 g of a compound is dissolved in 10 g of acetone there is elevation to 56.88^(@)C in b.p What is the mol.wt. of the comound ? (K_(b)" of acetone"=1.72 K kg mole^(-1))

Knowledge Check

  • The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_b , for benzene is 2.53 K kg mol^(-1) .

    A
    `58 g mol^(-1)`
    B
    `85 g mol^(-1)`
    C
    `93 g mol^(-1)`
    D
    `108 g mol^(-1)`
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