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Calculate the boiling of one molar aqueo...

Calculate the boiling of one molar aqueous solution (density=1.04 g `mL^(-1)`) of potanssium chloride `(K_(b)=0.52" K kg mol"^(-1))`

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To calculate the boiling point of a one molar aqueous solution of potassium chloride (KCl), we will follow these steps: ### Step 1: Identify the given data - Molarity (M) of KCl = 1 mol/L - Density of the solution = 1.04 g/mL - Boiling point elevation constant (K_b) for water = 0.52 K kg/mol ### Step 2: Calculate the mass of the solution ...
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Calculate the boiling point of a one molar aqueous solution (density 1.04 g "mL "^(1) ) of potassium chloride K_(b) for water = 0.52 K "mol "^(-1) . Atomic masses : K = 39, Cl = 35.5 )

Calculate the boiling point of a 1M aqueous solution (density 1.04 g Ml^(-1) ) of Potassium chloride (K_(b) " for water " =0.52 K kg "mol"^(-1)," Atomic masse " : K=39u, CI=39.9u) Assume, Potassium chloride is completely dissociated in solution.

Knowledge Check

  • Elevation of boiling point of 1 molar aqueous glucose solution ("density"=1.2g//ml) is

    A
    `"K"_("b")`
    B
    1.20 `"K"_("b")`
    C
    1.02`"K"_("b")`
    D
    0.98`"K"_("b")`

  • What is the boiling point of 1 molal aqueous solution of NaCl (K_b)=0.52 K molal^-1]

    A
    `99.48^@C`
    B
    `98.96^@C`
    C
    `100.52^@C`
    D
    `101.04^@C`

  • Calculate elevation in boiling point for 2 molal aqueous solution of glucose - (Given : K_(b(H_(2)O)) =0.5 K kg mol^(-1)).

    A
    1
    B
    4
    C
    3
    D
    2

    • Similar Questions

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    Calculate the freezing point of the one molar aqueous solution (density 1.04 g L^(-1) ) of KCl ( k_(f) for wateer = 1.86 kg mol^(-1) , atomic mass of K = 39 ,Cl = 35.5)

    Calculate the freezing point of a one-molar aqueous solution (density 1.06 g mL_(-1) ) of KBr. K_"f" for water = 1.86 K kg mol^(-1) . Atomic mass: K = 39, Br = 80.

    Calculate the boiling point of a solution prepared by adding 15.00 g of NaCl to 250 g of water . (K_(b) = 0.512 K kg mol^(-1) and molar mass of NaCl = 58.44 g mol^(-1) )

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    The boiling point of an aqueous solution is 100.18 .^(@)C . Find the freezing point of the solution . (Given : K_(b) = 0.52 K kg mol^(-1) ,K_(f) = 1.86 K kg mol^(-1))

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