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What will be the Van't Hoff factor for a...

What will be the Van't Hoff factor for a dilute aqueous solution of `BaCI_(2)` ?

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To determine the Van't Hoff factor (i) for a dilute aqueous solution of barium chloride (BaCl₂), we can follow these steps: ### Step 1: Understand the Dissociation of BaCl₂ Barium chloride is a strong electrolyte, which means it completely dissociates into its ions when dissolved in water. The dissociation can be represented as follows: \[ \text{BaCl}_2 (s) \rightarrow \text{Ba}^{2+} (aq) + 2 \text{Cl}^- (aq) \] ### Step 2: Count the Number of Ions Produced ...
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Knowledge Check

  • The van't Hoff factor for a very dilute aqueous solution of KAg(CN)_(2) is

    A
    4
    B
    3
    C
    2
    D
    none of these
  • The Van't Hoff factor for a dillute aqueous solution of glucose is

    A
    Zero
    B
    1
    C
    1.5
    D
    2
  • van't Hoff factor (i)

    A
    Is less than one in case of dissociation
    B
    is more than one in case of association
    C
    i=normal molecular mass /oberved molecular mass
    D
    i=observed molecular mass/normal molecular mass
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