Calculate the molarity of pure water. Given that density of pure wateris 1 g/mol.

Answer

55.55 M

Explanation

`"Mass of 1000 mL of pure water "= Vxxd=(1000 mL)xx(1g//mL)=1000 g`
`"Moles of water in 1000 g"=("Mass")/("Molar mass")=((1000g))/((18" g mol"^(-01)))=55.55 mol`
`"Molarity (M) "=("Moles of water")/("Volume of waster in litres")=((55.55 mol))/(1L)`
=55.55 mol/L = 55.55 M.