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If R(H) is the Rydberg constant, then th...

If `R_(H)` is the Rydberg constant, then the energy of an electron in the ground state of Hydrogen atom is

A

`R_(H)//C`

B

`R_(H)h//C`

C

`(hc)/(R_(H))`

D

`R_(H)hc`

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(n) = (R_(H)hc)/(n^(2))`
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Knowledge Check

  • If R_(H) represents Rydberg constant, then the energy of the electron in the ground state of hydrogen atom is

    A
    `- (hc)/(R_(H))`
    B
    `- (1)/(R_(H) ch)`
    C
    `-R_(H) ch`
    D
    `- (R_(H)c)/(h)`

  • If R is the Rydberg's constant, the energy of an electron in the ground state H atom is

    A
    `(Rc)/h`
    B
    `(-1)/(Rhc)`
    C
    `-Rhc`
    D
    `(vc)/R`

  • The ionization energy of hydrogen atom in the ground state is

    A
    13.6 MeV
    B
    13.6 eV
    C
    13.6 Joule
    D
    Zero

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    Hydrogen atom: The electronic ground state of hydrogen atom contains one electron in the first orbit. If sufficient energy is provided, this electron can be promoted to higher energy levels. The electronic energy of a hydrogen-like species (any atom//ions with nuclear charge Z and one electron) can be given as E_(n)=-(R_(H)Z^(2))/(n^(2)) where R_(H)= "Rydberg constant," n= "principal quantum number" Calculate the following : (a) the kinetic energy (in eV) of an electron in the ground state of hydrogen atom. (b) the potential energy (in eV) of an electron in the ground state of hydrogen atom.

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