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A sample of water under supply was found...

A sample of water under supply was found to boil at `102^(@)C` at normal temperature and pressure. It the water pure ? Will this water freeze at `0^(@)C` ? Comment.

Text Solution

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Under normal temperature and pressure, the boiling point temperature of pure water is `100^(@)C`. The boiling point of `102^(@)C` means that the given sample is impure and has non-volatile impurities present. This impure sample will have freezing point temperature below `0^(@)C`. Please remember that the presence of impurities raises the boiling point temperature of a liquid and lowers its freezing point.
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Knowledge Check

  • At what temperature (in Fahrenheit) pure water freezes?

    A
    32
    B
    0
    C
    48
    D
    37

  • Water will boil at 101.5^(@)C at which of the following pressure:

    A
    (a) `76 cm` of `Hg`
    B
    (b) `76 mm` of `Hg`
    C
    (c ) `gt 76 cm` of `Hg`
    D
    (d) `lt 76 cm` of `Hg`

  • On hilly reason, water boils at 95^@C . The temperature expressed in Fahrenheit scale is

    A
    `100^@F`
    B
    `200^@F`
    C
    `150^@F`
    D
    `203^@F`

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