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From a window, 60 metres high above the ...

From a window, 60 metres high above the ground, of a house in a street, the angles of elevation and respectively. Show that the height of the opposite house is `60(sqrt3+1)` metres.

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From a window (h metres high above the ground) of a house in a street, the angle of elevation and depression of the top and the foot of another house on the opposite side of the street are theta and phi respectively. Show that the height of the opposite house is h(1+tan theta cot phi) metres.

From a window 60 m high above the ground of a house in a street, the angle of elevation and depression of the top and the foot of another house on the opposite side of the street are 60^(@) and 45^(@) respectively. Show that the height of opposite house is 60(1+sqrt(3)) metres.

Knowledge Check

  • From a window (h m high above the ground) of a house in a street, the angle of elevation and depression of the top and the foot of another house on the opposite side to the street are and 0, respectively. Then, the height of the opposite house is

    A
    `hcotthetacotphi`
    B
    `h(cotthetacotphi+1)`
    C
    `htanthetacotphi`
    D
    `h(tanthetacotphi+1)`

  • From the top of a house A in a street, the angles of elevation and depression of the top and foot of another house B on the opposite side of the street are 60^(@) and 45^(@) , respectively. If the height of house A is 36 m, then what is the height of house B? (Your answer should be nearest to an Integer.

    A
    91 cm
    B
    93 m
    C
    94 m
    D
    98 m

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    From a window 15m high above the ground in a street,the angle of elevation and depression of the top and foot of another house on the opposite side of the street are 30^(@) and 45^(@) respectively.Then the height of opposite house in meters is

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