Home
Class 11
MATHS
A line is drawn through a fix point P(al...

A line is drawn through a fix point P(`alpha, beta`) to cut the circle `x^2 + y^2 = r^2` at A and B. Then PA.PB is equal to :

A

`(alpha-beta)^(2)+r^(2)`

B

`alpha^(2)+beta^(2)-r^(2)`

C

`(alpha+beta)^(2)+r^(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CONIC SECTION

    NAGEEN PRAKASHAN|Exercise Exercise 11.1|15 Videos
  • CONIC SECTION

    NAGEEN PRAKASHAN|Exercise Exercise 11.2|12 Videos
  • CONIC SECTION

    NAGEEN PRAKASHAN|Exercise Exercise 11F|10 Videos
  • COMPLEX NUMBERS AND QUADRATIC EQUATION

    NAGEEN PRAKASHAN|Exercise MISCELLANEOUS EXERCISE|20 Videos
  • INTRODUCTION OF THREE DIMENSIONAL GEOMETRY

    NAGEEN PRAKASHAN|Exercise Miscellaneous Exercise|6 Videos

Similar Questions

Explore conceptually related problems

A line is drawn through a fix point P(alpha,beta) to cut the circle x^(2)+y^(2)=r^(2) at A and B. Then PAt the circle x^(2)+y^(2)=r^(2) at A and B. Then PAt PB is equal to:

A line drawn through the point P(4,7) cuts the circle x^(2)+y^(2)=9 at the points A and B .Then PA.PB is equal to:

Knowledge Check

  • A line is drawn through a fixed point P(alpha, B) to cut the circle x^(2)+y^(2)=r^(2) at A and B. Then PA.PB is equal to

    A
    `(alpha+beta)^(2)-r^(2)`
    B
    `(alpha^(2)+beta^(2)-r^(2)`
    C
    `(alpha-beta)^(2)+r^(2)`
    D
    None of the above
  • A line is drawn through a fixed point P(h, k) to cut the circle x^(2)+y^(2)=a^(2) at A and B. Then PA, PB is equal to

    A
    `(h+k)^(2)-a^(2)`
    B
    `h^(2)+k^(2)-a^(2)`
    C
    `(h-k)^(2)+a^(2)`
    D
    none of these
  • A line is drawn through the point P(3,11) to cut the circle x^(2)+y^(2)=9 at A and B. Then PA.PB is equal to

    A
    9
    B
    121
    C
    205
    D
    139
  • Similar Questions

    Explore conceptually related problems

    The tangent at the point (alpha, beta) to the circle x^2 + y^2 = r^2 cuts the axes of coordinates in A and B . Prove that the area of the triangle OAB is a/2 r^4/|alphabeta|, O being the origin.

    If a line passes through the point P(1,-2) and cuts the x^2+y^2-x-y= 0at A and B, then themaximum of PA+PB is

    A line passing through the points A(1.-2) cuts the circle x^(2)+y^(2)-y=0 at P and Q Then the maximum value of |AP-AQ| is

    A line is drawn through the point P(3,11) to cut the circle x^2+y^2=9 at A and B. Then, PA cdot PB is equal to

    A line passes through the point P (5,6) outside the circle x^(2) + y ^(2) = 12 and meets the circle at A and B. The value of PA. PB is equal to