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The velocity of the particle at any time...

The velocity of the particle at any time t is given by `vu = 2t(3 - t) m s^(-1)`. At what time is its velocity maximum?

A

2 s

B

3 s

C

2/3 s

D

3/2 s

Text Solution

Verified by Experts

The correct Answer is:
D
Given : `v = 2t(3 - t)` or v = `6t - 2t^(2)`
`(dv)/(dt) = 6 - 4t`, For maximum velocity, `(dv)/(dt) = 0`
`therefore 6 - 4t = 0 ` or `t = 3/2` s
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Knowledge Check

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