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The simple pendulum A of mass m(A) and l...

The simple pendulum A of mass `m_(A)` and length l is suspended from the trolley B of mass `m_(B)`. If the system is released from rest at `theta = 0`, determine the velocity `v_(B)` of the trolley and tension in the string when `theta = 90°`. Friction is negligible.

A

`v_(B)=(m_(A))/(m_(B))sqrt((2gl)/(1+m_(A)//m_(B)))`

B

`v_(B)=(m_(A))/(m_(B))sqrt((4gl)/(1+m_(A)//m_(B)))`

C

`v_(B)=(m_(A))/(m_(B))sqrt((2gl)/(1-m_(A)//m_(B)))`

D

`v_(B)=(m_(A))/(m_(B))sqrt((4gl)/(1-m_(A)//m_(B)))`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A simple pendulum of bob mass m and length l is displaced from its mean position O to a point A and then released . If v is the velocity of the bob at O, h is the height of string of pendulum when bob passes through point O is /are (neglect friction )

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    `(2mgh)/(l)`
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    A
    `tan^(-1)((a)/(g))`
    B
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    D
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