The simple pendulum A of mass `m_(A)` and length l is suspended from the trolley B of mass `m_(B)`. If the system is released from rest at `theta = 0`, determine the velocity `v_(B)` of the trolley and tension in the string when `theta = 90°`. Friction is negligible.

Options

A. `v_(B)=(m_(A))/(m_(B))sqrt((2gl)/(1+m_(A)//m_(B)))`
B. `v_(B)=(m_(A))/(m_(B))sqrt((4gl)/(1+m_(A)//m_(B)))`
C. `v_(B)=(m_(A))/(m_(B))sqrt((2gl)/(1-m_(A)//m_(B)))`
D. `v_(B)=(m_(A))/(m_(B))sqrt((4gl)/(1-m_(A)//m_(B)))`

Answer

A