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In the spectrum of hydrogen atom, the ra...

In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is

A

`(5)/(27)`

B

`(1)/(93)`

C

`(4)/(9)`

D

`(3)/(2)`

Text Solution

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The correct Answer is:
A
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In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelength in the Balmer series is :

In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelength in the Balmer series is :

Knowledge Check

  • The longest wavelength limit of Lyman series is

    A
    `4/(3 xx 109670)` cm
    B
    `3/(4 xx 109670)` cm
    C
    `(4 xx 109670)/3` cm
    D
    `(3 xx 109670)/4` cm

  • The shoretest wavelength in Lyman series is 91.2 nm. The longest wavelength of the series is

    A
    121.6 nm
    B
    182.4 nm
    C
    243. 4nm
    D
    364.8 nm

  • If the shortest wavelength of H atom in Lyman series is x, then longest wavelength in Balmer series of H–atom is

    A
    `(9x)/(5)`
    B
    `(36x)/(5)`
    C
    `(x)/(4)`
    D
    `(5x)/(9)`

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    In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is (x)/(27) . Find x .

    Find the ratio of the longest wavelength in the Paschen series to the shortest wavelength in the Balmer series.

    Find the ratio of longest wavelangth in Paschen series to shortest wavelength in Balmer series.

    If the shortest wavelenth of H atom in Lyman series is x, then longest wavelength in Balmer series of He^(+) is

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