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Taking the wavelength of first Balmer li...

Taking the wavelength of first Balmer line in hydrogen spectrum (`n = 3` to `n = 2`) as 660 nm, the wavelength of the `2^(nd)` Balmer line (`n = 4` to `n = 2`) will be:

A

889.2 nm

B

488.9 nm

C

388.9 nm

D

642.7 nm

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The correct Answer is:
B
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