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Calculate milli equilvalent of washing s...

Calculate milli equilvalent of washing soda required to remove its hardness from one litre hard water contains `"18.00 mg Mg"^(2+)`

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To solve the problem of calculating the milli-equivalents of washing soda required to remove the hardness from 1 liter of hard water containing 18.00 mg of Mg²⁺, we can follow these steps: ### Step 1: Understand the Concept of Milli-Equivalent A milli-equivalent (mEq) is a unit that expresses the amount of a substance in terms of its reactive capacity. For ions, it is calculated based on the number of moles of the ion and its charge. ### Step 2: Calculate the Equivalent Weight of Magnesium The equivalent weight of an ion can be calculated using the formula: \[ \text{Equivalent Weight} = \frac{\text{Molar Mass}}{n} \] where \( n \) is the number of electrons transferred (valency). For magnesium (Mg): - Molar Mass = 24 g/mol - Valency (n) = 2 Thus, the equivalent weight of Mg is: \[ \text{Equivalent Weight of Mg} = \frac{24 \, \text{g/mol}}{2} = 12 \, \text{g/equiv} \] ### Step 3: Convert the Mass of Magnesium to Grams We have 18.00 mg of Mg²⁺. We need to convert this to grams: \[ 18.00 \, \text{mg} = 18.00 \times 10^{-3} \, \text{g} = 0.018 \, \text{g} \] ### Step 4: Calculate the Number of Equivalents of Magnesium Using the equivalent weight calculated in Step 2, we can find the number of equivalents of Mg²⁺: \[ \text{Number of Equivalents} = \frac{\text{Mass (g)}}{\text{Equivalent Weight (g/equiv)}} \] \[ \text{Number of Equivalents of Mg} = \frac{0.018 \, \text{g}}{12 \, \text{g/equiv}} = 0.0015 \, \text{equiv} \] ### Step 5: Convert Equivalents to Milli-Equivalents Since 1 equivalent = 1000 milli-equivalents, we convert the number of equivalents to milli-equivalents: \[ \text{Milli-Equivalents of Mg} = 0.0015 \, \text{equiv} \times 1000 = 1.5 \, \text{mEq} \] ### Step 6: Relate to Washing Soda Washing soda (sodium carbonate, Na₂CO₃) reacts with Mg²⁺ to remove hardness. The amount of washing soda required in milli-equivalents will be equal to the milli-equivalents of Mg²⁺ present in the water. Thus, the milli-equivalents of washing soda required is also: \[ \text{Milli-Equivalents of Washing Soda} = 1.5 \, \text{mEq} \] ### Final Answer The milli-equivalent of washing soda required to remove the hardness from 1 liter of hard water containing 18.00 mg of Mg²⁺ is **1.5 mEq**. ---
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Knowledge Check

  • One litre hard water contains 12.00 mg Mg^(2+) Milliequivalents of washing soda required to remove its hardness is

    A
    1
    B
    `12.16`
    C
    `1 xx 10^(-3)`
    D
    `12.16 xx 10^(-3)`
  • One litre hard water contains 12.00 mg Mg^(2+) millieqivalent of washing soda required to remove its hardness is

    A
    (a)1
    B
    (b)12.15
    C
    (c )`1xx10^(-3)`
    D
    (d)`12.5xx10^(-3)`
  • The amount of lime, Ca(OH)_(2) required to remove the hardness in 60 L of pond water containing 1.62 mg of calcium bicarbonate per 100 ml of water, will be :

    A
    `4.44g`
    B
    `0.222g`
    C
    `2.22 g`
    D
    `0.444 g`
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