Home
Class 12
PHYSICS
The orbit of geostationary satelite is c...

The orbit of geostationary satelite is circular , the time period of satellite depend on (I) Mass of the satellite
(ii) mass of the earth
(iii) Radius of the orbit
(iv) Height of the satellite from the surface of earth
which of the following is correct ?

A

has a circular orbit lying in an equatorial plane of the earth

B

appears stationary with respect to earth

C

is a preferred satellite for steady and reliable transmission and reception

D

is orbiting at a height of approximately `36000km` above the surface of earth in a circular orbit containing New Delhi in its plane.

Text Solution

Verified by Experts

D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    FIITJEE|Exercise Assertion & Reasoning type|1 Videos
  • GRAVITATION

    FIITJEE|Exercise Numerical based Questions|4 Videos
  • GRAVITATION

    FIITJEE|Exercise Solved problem (Objective)|15 Videos
  • GMP ASSESMENT

    FIITJEE|Exercise Numerical Based|61 Videos
  • HEAT AND TEMPERATURE

    FIITJEE|Exercise NUMERICAL BASES QUESTIONS|1 Videos

Similar Questions

Explore conceptually related problems

A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth, where R is the radius of the earth. The time period of another satellite at a height of 2.5 R from the surface of the earth is …… hours.

The orbital velocity of a satellite is given by the expression V = sqrt((GM)/(R + h)) , here M is the mass of the Earth, R is the radius of the Earth and 'h' is the height of the satellite from the surface of the Earth. Explain the reasons why the geostationary satellite is not possible to set in orbit around the Earth at two different heights from the surface of the Earth.

Knowledge Check

  • The orbit of geostationary satellite is circular, the time period of satellite depeds on (i) mass of the satellite, (ii) mass of earth, (iii) readius of the orbit and (iv) height of the satellite from the surface of the earth

    A
    (i) only
    B
    (i) and (ii)
    C
    (i), (ii) and (iii)
    D
    (ii), (iii) and (iv)
  • If the height of a satellite from the earth is negligible in comparison to the radius of the earth R , the orbital velocity of the satellite is

    A
    `gR `
    B
    `g//R2`
    C
    `sqrt(g//R)`
    D
    `sqrt(gR)`
  • A geostationary satellite is orbiting the earth at a height of 5R above the surface of the earth, R being the radius of the earth. The time period of another satellite in hours at a height of 2R form the surface of the earth is

    A
    `6/(sqrt(2))`
    B
    `5`
    C
    `10`
    D
    `6sqrt(2)`
  • Similar Questions

    Explore conceptually related problems

    A geostationary satellite is orbiting the earth at a height of 6R above the surface oof earth where R is the radius of the earth .The time period of another satellite at a distance of 3.5R from the centre of the earth is ….. hours.

    Radius of a geostationary satellite revolving round the earth is 'r'. Then period of revolution of another satellite revolving in an orbit of radius r/2 is

    Match the Column I with Column II For a satellite in circular orbit (where M_(E) is the mass of the earth , m is the mass of the satellite and r is the radius of the orbit )

    The orbital velocity of an satellite in a circular orbit just above the earth's surface is v . For a satellite orbiting at an altitude of half of the earth's radius, the orbital velocity is

    A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth, where R is the radius of the earth. What is the time period of another satellite orbiting at a height of 2.5 R from the surface of the earth ?