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For gaseous reaction N2(g) +3H2(g) hArr ...

For gaseous reaction `N_2(g) +3H_2(g) hArr 2NH_3(g)` , the units of equilibrium constant `K_p` are ………..

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For the reaction, N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) , the units of K_(p) are …………

1 mol of nitrogen is mixed with 3 mol of hydrogen in a 4 L container. If 0.25% of nitrogen is converted to ammonia by the following reaction N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) then calculate the equilibrium constant K_(c) in concentration units. What will be the value of K_(c) for the following equilibrium? 1/2 N_(2)(g)+3/2 H_(2)(g) hArr NH_(3)(g)

Knowledge Check

  • For the reaction N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g), DeltaH=?

    A
    `DeltaE+2RT`
    B
    `DeltaE-2RT`
    C
    `DeltaE+RT`
    D
    `DeltaE-RT`

  • For the reaction H_2(g) +I_2(g) hArr 2HI(g) , the equilibrium constant K_p Changes with

    A
    total pressure
    B
    catalyst
    C
    the amount of `H_2 and I_2` present
    D
    temperature

  • In the reaction N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g) , the value of the equlibrium constant depends on

    A
    Volume of the reaction vessel
    B
    Total pressure of the system
    C
    The initial concentration of nitrogen and hydrogen
    D
    The temperature

    • Similar Questions

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    If the equilibrium constant for the reaction N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) at 750 K is 49, then the equilibrium constant for the reaction NH_(3)(g)hArr1/2N_(3)(g)+3/2H_(2)(g) at the same temperaturee is

    For an equlibrium reaction N_2(g) + 3H_2(g) harr 2NH_3(g) , K_c = 64. what is the equilibriu constant for the reaction NH_3(g) harr 1/2N_2(g) + 3/2 H_2(g)

    For the reaction, N_2(g) + 3H_2(g) harr 2NH_3(g) constant can be given as

    For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) The equilibrium constant K_(p) changes with

    For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

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