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K(a)1 for butyric acid is 2xx10^(-5) ....

`K_(a)`1 for butyric acid is `2xx10^(-5)` .Calculate pH in `0.2 ` M aqueous solution butrae

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`{:(NaBu,+,H_(2)O,hArr,NaOH,+,BuH),(1,,,,0,,0),((1-h),,,,h,,h):}`
` [OH^(-)] = Ch = C sqrt((Kh)/C)= sqrt (K_(n)C) = sqrt((K_(w)C)/(K_(a)))`
` sqrt((10^(-14)xx6.02 )/(2xx10^(-5))) = sqrt(10^(-19)) = 10^(-5)`
`[H^(+)] = 10^(-9)`
` :. pH = 9 `
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