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Match the Column- I with Column- II: ...

Match the Column- I with Column- II:
`{:(,"Column-I",,"Column-II"),((A),0.21M Ca_(3)(PO_(4))_(2),(p),"Solution with highest boiling point"),((B),0.1 M NaCl, (q),"Solution with van't Hoff factor greater than 1"),((C),0.1 M "glucose",(r),"Solution with lowest osmotic pressure"),((d),0.1M CaCl_(2),(s),"Solution with lowest freezing point"),(,,(t),"Van't Hoff factors"(1+2alpha)):}`

Text Solution

AI Generated Solution

To solve the problem of matching Column-I with Column-II, we need to analyze the properties of the given solutions based on their molarity and van't Hoff factors. Let's break it down step by step. ### Step 1: Identify the van't Hoff factors (i) for each solution. 1. **0.21 M Ca₃(PO₄)₂**: - Dissociates into 3 Ca²⁺ and 2 PO₄³⁻ ions. - Total particles = 3 + 2 = 5. - Therefore, \( i = 5 \). ...
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[E] Match the solutions in Column-I with their colligative properties in Column-II : {:(,"Column-I",,"Column-II"),("(a)",0.1M Ca_(3)(PO_(4))_(2),"(p)","Solution with highest boiling point"),("(b)",0.1M NaCl,"(q)","Solution with van't Hoff factor greater than 1"),("(c)",0.1 M " glucose","(r)","Solution with lowest osmotic pressure"),("(d)",0.1 M CaCl_(2),"(s)","Solution with lowest freezing point"):} [Note : Assume that the electrolytes are completely ionised.]

{:("Column-I","Column-II"),((A)"0.1 M "Al_2(SO_4)_3, (p)"Solution with highest boiling point"),((B)"0.1 M"AlPO_4,(q)"Van't Hoff factor is greater than 1"),((C )"0.1 M urea",(r)"Solution with lowest osmotic pressure"),((D)"0.1 M"MgCl_2,(s)"Solution with lowest freezing point"):}

Knowledge Check

  • 1.2 % NaCl solution is isotonic with 7.2 % glucose solution. What will be the van't Hoff factor, i?

    A
    0.5
    B
    1
    C
    2
    D
    6

  • vant Hoff factor for 0.1 M ideal solution is

    A
    `0.1`
    B
    1
    C
    `0.01`
    D
    none of these

  • What will be the degree of dissociation of 0.1 M Mg(NO_3)_2 solution if van't Hoff factor is 2.74 ?

    A
    `75%`
    B
    `87%`
    C
    `100%`
    D
    `92%`

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    For a solution of AlCl_(3) in water, the Van't Hoff factor (i) is greater than 1 .

    {:("Column I (Solvent)","Column II "("Value of "K_(f)or K_(b))),("(A) 0.1 M Glucose sol.","(p) Lowest freezing point"),("(B) 0.1 M Sucroe sol.","(q) Highest freezing point"),("(C) 0.1 M "BaCl_(2)" sol.","(r) Lowest osmotic pressure"),("0.1 M "Ca(NO_(3))_(2)" sol.","(s) Highest osmotic pressure"):}

    Elevation in boiling point of 0.1 m CaCl_(2) , solution less / more than 0.1 m NaCl solution.

    1.2% NaCl solution is isotonic with 7.2% glucose solution. What will be the van’t Hoff factor, i?

    Van't Hoff factor for 0.1 M ideal solution is

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