Home
Class 12
CHEMISTRY
75.2 g of C(6)H(5)OH (phenol) is dissolv...

`75.2 g` of `C_(6)H_(5)OH` (phenol) is dissolved in a solvent of `K_(f) = 14`. If the depression in freezing point is `7K`, then find the percentage of phenol that dimerises.

Text Solution

Verified by Experts

The correct Answer is:
0.75
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LIQUID SOLUTION

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (SUBJECTIVE) level-II|15 Videos

  • LIQUID SOLUTION

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) level-I|55 Videos

  • LIQUID SOLUTION

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (SUBJECTIVE) level-I (FILL IN THE BLANKS)|9 Videos

  • IONIC EQUILIBRIUM

    FIITJEE|Exercise SINGLE INTEGER ANSWER QUESTIONS|4 Videos

  • NUCLEIC ACID AND VITAMIN

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE)|15 Videos

Similar Questions

Explore conceptually related problems

In an experiment, 72.5 g of C_(6)H_(5)OH (phenol) is dissolved in a solvent of K_(f)=14 . If the depression in freezing point is 7 K , find the percentage of phenol that dimerizes.

72.2g of C_(6)H_(5)OH (phenol) is dissolved in a solvent of K_(f)=14 . If the depression in freezing point is 7K then find the % of phenol that dimerises [Give your answer divide by 25%]

72.5 g of C_6H_5OH (phenol) is dissolved in a solvent of K_f ​= 14. If the depression in freezing point is 7K then find the % of phenol that dimerises [Give your answer divide by 25%]:-

75.2 g of C_(6)H_(5)OH (phenol) is dissolved in 1 kg of solvent of k_(f)= 14 K "molality"^(-1) . If depression in freezing point is 7 K . Calculate % of phenol that dimerises.

1575.2 g of C_(6)H_(5)OH (phenol) is dissolved in 960 g of a solvent of solvent of K_(f)=14 K kg mol^(-1) . If the depression in freezing point is 7 K , then find the percentage of phenol that dimerizes.

72.5g of phenol is dissolved in 1 kg of a solvent (K_(f)=14) which leads to dimerization of phenol and freezinfg point is lowered by 7 kelvin. What percentage of toal phenol is present in dimeric form?

72.5g of phenol is dissolved in 1kg of a solvent (k_(f) = 14) which leads to dimerization of phenol and freezing point is lowered by 7 kelvin. What percent of total phenol is present in dimeric form?

Molecules of benzoic acid (C_(6)H_(5)COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30g of benzene shows a depression in freezing point equal to 2K. If the percentage association of the acid to form dimer in the solution is 80, then w is : (Given that K_(f)=5K Kg "mol"^(-1) Molar mass of benzoic acid =122 g "mol"^(-1) )

1.5 g of Ba(NO_(3))_(2) dissolved in 100g of water shows a depression in freezing point equal to 0.28^(@)C . What is the percentage dissociation of the salt ? ( k_(f) for water = 1.86 K//m and molar mass of Ba(NO_(3))_(2) = 261 ).

A hypothetical solute AB is 50% dissociated at freezing point and 80% dissociated at boiling point of solution.If 2 mole of solute is dissolved in 500 g solvent and the difference in boiling point and freezing point of solvent is 100K then calculate the difference in boiling point and freezing point of solution. [Given K_(b)= 0.5Kkgmol^(-1) K_(f)=2.0Kkgmol^(-1) ]

Home
Profile