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The total pressure exerted in ideal bina...

The total pressure exerted in ideal binary solution is given by `P=P_(A)^(@)X_(A)+P_(B)^(@)X_(B)` where `P_(A)^(@)&P_(B)^(@)` are the respective vapour pressure of pure components and `X_(A)&X_(B)` are their mole fraction in liquid phase. And composition of the vapour phase is determined with the help of Datton's law partial pressure: `Y_(A)=(P_(A)^(@)X_(A))/(P)`
If total pressure exerted in an ideal binary solution is given by `P=(5400)/(60+30Y_(A))mm` of Hg.
If the value of `Y_(A)=0.4` then the value of `X_(B)` is:

A

`0.6`

B

`0.25`

C

`0.4`

D

`0.5`

Text Solution

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The correct Answer is:
D
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The total pressure exerted in ideal binary solution is given by P = P_(A)^(@)X_(A) + P_(B)^(@) X_(B) " where " P_(A)^(@) & P_(B)^(@) are the respective vapour pressure of pure components and X_(A) & X_(B) are their mole fraction in liquid phase. And composition of the vapour phase is determined with the help of Dalton's law of partial pressure. Y_(A) = (P_(A)^(@) X_(A))/(P) If total pressure exerted in an ideal binary solution is given by P = (5400)/(60 + 30Y_(A))mm " of " Hg . The value of P_(A)^(@) is

The total pressure exerted in ideal binary solution is given by P = P_(A)^(@)X_(A) + P_(B)^(@) X_(B) " where " P_(A)^(@) & P_(B)^(@) are the respective vapour pressure of pure components and X_(A) & X_(B) are their mole fraction in liquid phase. And composition of the vapour phase is determined with the help of Dalton's law of partial pressure. Y_(A) = (P_(A)^(@) X_(A))/(P) If total pressure exerted in an ideal binary solution is given by P = (5400)/(60 + 30Y_(A))mm " of " Hg . The more volatile liquid is

Knowledge Check

  • The total pressure exerted in ideal binary solution is given by P=P_(A)^(@)X_(A)+P_(B)^(@)X_(B) where P_(A)^(@)&P_(B)^(@) are the respective vapour pressure of pure components and X_(A)&X_(B) are their mole fraction in liquid phase. And composition of the vapour phase is determined with the help of Datton's law partial pressure: Y_(A)=(P_(A)^(@)X_(A))/(P) If total pressure exerted in an ideal binary solution is given by P=(5400)/(60+30Y_(A))mm of Hg. The value of P_(A)^(@) is:

    A
    40 mm of Hg
    B
    30 mm of Hg
    C
    60 mm of Hg
    D
    90 mm of Hg

  • The total pressure exerted in ideal binary solution is given by P=P_(A)^(@)X_(A)+P_(B)^(@)X_(B) where P_(A)^(@)&P_(B)^(@) are the respective vapour pressure of pure components and X_(A)&X_(B) are their mole fraction in liquid phase. And composition of the vapour phase is determined with the help of Datton's law partial pressure: Y_(A)=(P_(A)^(@)X_(A))/(P) If total pressure exerted in an ideal binary solution is given by P=(5400)/(60+30Y_(A))mm of Hg. The more volatile liquid is:

    A
    liquid A
    B
    liquid B
    C
    both are same
    D
    it depends on the amount of A and B

  • The total pressure exerted in ideal binary solution is given by P = P_(A)^(@)X_(A) + P_(B)^(@) X_(B) " where " P_(A)^(@) & P_(B)^(@) are the respective vapour pressure of pure components and X_(A) & X_(B) are their mole fraction in liquid phase. And composition of the vapour phase is determined with the help of Dalton's law of partial pressure. Y_(A) = (P_(A)^(@) X_(A))/(P) If total pressure exerted in an ideal binary solution is given by P = (5400)/(60 + 30Y_(A))mm " of " Hg . If the value of Y_(A) = 0.4 then the value of X_(B) is

    A
    0.6
    B
    0.25
    C
    0.4
    D
    0.5

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    The total vapour pressure of a binary solution is gives by P = ( 100X_(A) + 260 X_(B) )mm Hg where, X_(A)and X_(B) are the molefractions of components A and B. This indicates that the:

    Vapour pressure of a solvent is the pressure exterted by vapour when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent of nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate. The vapour pressure of a mixture obtained by mixing two valatile liquids is given by P_(M) = P_(A)^(@).X_(A)+P_(B)^(@).X_(B) where P_(A)^(@) and P_(B)^(@) are vapour pressures of pure components A and B and X_(A), X_(B) are their mole fractions in mixture. For solute-solvent system, the relatio becomes P_(M) = P_(A)^(@).X_(A) where B is non-volatile solute. A mixture of two volatile liquids A and B 1 and 3 moels respectively has a V.P of 300 mm at 27^(@)C . IF one mole of A is further added to this solution, the vapour pressure becomes 290 mm at 27^(@)C . The vapour pressure of A is:

    For an ideal binary liquid with P_(A)^(@) gt P_(B)^(@) , which relation between X_(A) ? (mole fraction of A in liquid phase) and Y_(A) (mole fraction of A in vapour phase) is correct.

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    Vapour pressure of a solvent is the pressure exterted by vapour when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent of nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate. The vapour pressure of a mixture obtained by mixing two valatile liquids is given by P_(M) = P_(A)^(@).X_(A)+P_(B)^(@).X_(B) where P_(A)^(@) and P_(B)^(@) are vapour pressures of pure components A and B and X_(A), X_(B) are their mole fractions in mixture. For solute-solvent system, the relatio becomes P_(M) = P_(A)^(@).X_(A) where B is non-volatile solute. The vapour pressure of benzene and its solution with a non-electrolyte are 640 and 600 mm respectively. The molality of solution is:

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