Home
Class 12
CHEMISTRY
At 25^(@) the specific conductance of a ...

At `25^(@)` the specific conductance of a saturated solution of AgCl after subtracting the specific conducatnce of water is `1.82 xx 10^(4) Sm^(-1)`. The molar conductance at infinite dilution of `AgNO_(3), HNO_(3)` and HCl are respectively `133.0 xx 10^(-4), 421.0 xx 10^(-4) and 426 xx 10^(-4) S m^(2) "mol"^(-1)`. Find the solubility of AgCl. Write down the half cell reaction and calculate standard reduction potential for that the half Pt | 50mL 0.5 M KCl solution in which few drops of 0.1 M `E_(Ag, Ag)^(0)=0.80V.`

Text Solution

Verified by Experts

The correct Answer is:
`1.32 xx 10^(-5)" mol dm"^(-3)`
0.224 V
Half cell reactions
`AgCl(s)+e^(-) to Ag(s)+Cl^(-) (aq)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    FIITJEE|Exercise Exercise 3|1 Videos

  • ELECTROCHEMISTRY

    FIITJEE|Exercise Exercise 4|3 Videos

  • ELECTROCHEMISTRY

    FIITJEE|Exercise Exercise 1|1 Videos

  • CONCEPT OF ACIDS AND BASES

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|4 Videos

  • ELECTROPHILIC AROMATIC SUBSTITUTION

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS INDICATED BY DIGITAL INTERGER|1 Videos

Similar Questions

Explore conceptually related problems

At 25^@C the specific conductance of a saturated solution of AgCl after substracting the specific conductance of water is 1.82 xx 10^(-4)Sm^(-1). The molar conductance at Infinite dilution of AgNO_3, HNO_3, and HCI are respectively, 133.0 xx 10^(-4), 421.0 xx 10^(-4) and 426.0 xx 10^(-4)S m^2 mol^(-1). Write down half cell reaction and calculate standard reduction potential for the half cell: Pt|50 mL 0.5 M KCI solution, in which few drops of 0.1 M solution of AgNO_3 is added to precipitate out some AgCl. E_(Ag^(+),Ag)^(0)=0.80V

The specific conductance of a saturated solution of AgCl at 25^(@)C after subtracting the specific conductance of conductivity of water is 2.28 xx 10^(-6) mho cm^(-1) . Find the solublity product of AgCl at 25^(@)C . (Lambda_(AgCl)^(@) = 138.3 "mho cm"^(2))

Knowledge Check

  • Specific conductance of 0.1 M nitric acid is 6.3xx10^(-2) ohm^(-1) cm^(-1) . The molar conductance of the solution is

    A
    630 `ohm^(-1)` `cm^(2)` `mol^(-1)`
    B
    315 `ohm^(-1)` `cm^(2)` `mol^(-1)`
    C
    6.300 `ohm^(-1)` `cm^(2)` `mol^(-1)`
    D
    63.0 `ohm^(-1)` `cm^(2)` `mol^(-1)`

  • Specific conductance of 0.1M nitric acid is 6.3xx10^(-2)ohm^(-1)cm^(-1) . The molar conductance of the solution is:

    A
    `630ohm^(-1)cm^(2)"mol"^(-1)`
    B
    `315ohm^(-1)cm^(2)"mol"^(-1)`
    C
    `100ohm^(-1)cm^(2)"mol"^(-1)`
    D
    `6.300ohm^(-1)cm^(2)"mol"^(-1)`

  • The specific conductance of a saturated AgCl solution is found to be 1.86 xx 10^(-6) S cm^(-1) and that for water is 6.0 xx 10^(-8) S cm^(-1). The molar conductance of AgCl at infinite dilution is 180 S cm^(2) mol^(-1). The solubility of AgCl is:

    A
    `2 xx 10 ^(-7) mol L ^(-1)`
    B
    `2 xx 10 ^(-7) mol L ^(-1)`
    C
    `xx10 ^(-7) mol L ^(-1)`
    D
    `2 xx 10 ^(-14)mol L ^(-1)`

    • Similar Questions

    Explore conceptually related problems

    The conductivity of a saturated solution of AgCl at 25^(@)C after subtracting the conductivity of water is 2.28 xx 10^(-6) S cm^(-1) . Calculate the solubility product of AgCl at 25^(@)C if Lambda_(m)^(0) (AgCl) 138.3 S cm^(2) mol^(-1)

    The specific conductance of a salt of 0.01 M concentration is 1.061 xx 10^(-4) . Molar conductance of the same solution will be :

    The specific conductance of a salt of 0.05 M concentration is 1.061 xx10^(-4)" Scm"^(-1) Molar conductance of the same solution will be:

    The conductivity of a saturated solution CaF_(2) after deducting the contribution from water is 4.0xx10^(-5)Scm^(-1) . If molar conductivity of CaF_(2) at infinite dilution is 200Scm^(2)mol^(-1) , then the solubility product of CaF_(2) is

    Specific conductivity of 0.01N H_(2)SO_(4) solution is 6 xx 10^(-3) S cm^(-1) . Its molar conductivity is

    Home
    Profile