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The limiting molar conductances wedge^(i...

The limiting molar conductances `wedge^(infty)` for NaCl, KBr and KCl are 126, 152 and 150 S`cm^(2) mol^(–1)` respectively. The `wedge^(infty)` for NaBr will be:

A

302 S `cm^(2) mol^(–1)`

B

176 S `cm^(2) mol^(–1)`

C

278 S `cm^(2) mol^(–1)`

D

`128 S cm^(2) mol^(–1)`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • The limiting molar conductivities ^^ for NaCl, KBr and KCl are 126,152 and 150 S cm^(2)mol^(-1) respectively. The ^^ for NaBr is

    A
    278 S `cm^(2)mol^(-1)`
    B
    176 S `cm^(2)mol^(-1)`
    C
    128S `cm^(2)mol^(-1)`
    D
    302 S `cm^(2)mol^(-1)`
  • The limiting molar conductivities ^^ ^(@) for NaCl , KBr , and KCl are 126 , 152 and 150 S cm^(2) mol^(-1) respectively. The ^^ ^(@) for NaBr_________.

    A
    `278 S cm^(2) mol^(-1)`
    B
    `176 S cm^(2) mol^(-1)`
    C
    `128 S cm^(2)mol^(-1)`
    D
    `302 S cm^(2) mol^(-1)`
  • The limiting molar conductivities Lambda^(@) for NaCl,KBr nd KCl are 126,152 and 150 S cm^(2) "mol"^(-1) respectively. The Lambda^(@) for NaBr is:

    A
    `128S cm^(2) "mol"^(-1)`
    B
    `176 S cm^(2) "mol"^(-1)`
    C
    `278S cm^(2) "mol"^(-1)`
    D
    `302 S cm^(2) "mol"^(-1)`
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