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The [OH^(-)] in 100mL of 0.016M HCl(aq) ...

The `[OH^(-)]` in `100mL` of `0.016M HCl(aq)` is

A

`6.25xx10^(-12)M`

B

`3xx10^(-10)M`

C

`6.25xx10^(-13)M`

D

`1.6xx10^(-3)M`

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Calculate the [OH^(-)] of a solution after 100 mL of 0.1 M MgCl_(2) is added to 100 mL 0.2 M NaOH K_(sp) of Mg(OH)_(2) is 1.2 xx10^(-11) .

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Knowledge Check

  • The [OH^-] in 100.0 mL of 0.016 M-HCl(aq) is :

    A
    `5xx10^12 M`
    B
    `3xx10^(-10) M`
    C
    `6.25xx10^(-13) M`
    D
    `2.0xx10^(-9) M`

  • The number of Cl^(-) ions in 100 mL of 0.001 M HCl solution is

    A
    `6.022xx10%(23)`
    B
    `6.022xx10^(20)`
    C
    `6.022xx10^(19)`
    D
    `6.022xx10^(24)`

  • The number of Cl^(-) ions in 100 mL of 0.001 M HCl solution is

    A
    `6.022 xx 10^(23)`
    B
    `6.022 xx 10^(23)`
    C
    `6.022 xx 10^(19)`
    D
    `6.022 xx 10^(24)`

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