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pH calculation upon dilute of strong aci...

`pH` calculation upon dilute of strong acid solution is generally done by equating `n_(H)` in original solution & diluted solution.However . If strong acid solution is very dilute then `H^(+)` from water are also to be considered take `log3.7=0.568` and answer the following questions.
A `1` litres solution of `pH=4`(solution of a strong acid ) is added to the `7//3` litres of water.What is the `pH `of resulting solution?

A

`4.52`

B

`4.365`

C

`4.4`

D

`4.432`

Text Solution

Verified by Experts

Initial `pH=4`
`[H^(+)]=10^(-4)`
`N_(1)V_(1)=N_(2)V_(2)rArr 10^(-4)=N_(2)xx[1+(7)/(3)]`
`10^(-4)=N_(2)xx(10)/(3)rArr N_(2)=3xx10^(-5)" " gt10^(-6)`
so `[H^(+)]` of water is not consider
`[H^(+)]=3xx10^(-5)`" " so" "`pH=5-log(3)`" "`=5-0.48=4.52`
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pH calculation upon dilute of strong acid solution is generally done by equating n_(H) in original solution & diluted solution.However . If strong acid solution is very dilute then H^(+) from water are also to be considered take log3.7=0.568 and answer the following questions. A 1 litre solution of pH=6 (solution of a strong acid) is added to the 7//3 litres of water.What is the pH of resulting solution? Neglect the common ion effect on H_(2)O .

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Knowledge Check

  • 1 litre solution containing 490 g of sulphuric acid is diluted to 10 litre with water. What is the normality of the resulting solution ?

    A
    0.5 N
    B
    1.0 N
    C
    5.0 N
    D
    10.0 N

  • On diluting a buffer solution, its pH

    A
    Increases
    B
    Decreases
    C
    Remains same
    D
    Cannot be predicted

  • On dilution, the pH of a basic solution

    A
    increases
    B
    remains the same
    C
    decreases
    D
    may increase ordecrease depending upon the nature of the solution