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Calculate the pH of a given mixtures. ...

Calculate the pH of a given mixtures.
(a) `(4g CH_(3)COOH+6g CH_(3)COONa)` in 100 mL of mixture, (`K_(a)` for `CH_(3)COOH=1.8xx10^(-5))`
(b) 5 mL of `0.1MBOH+250` mL of `0.1 MBCI`, (`K_(a)` for `MOH=1.8xx10^(-5))`
(c ) (`0.25` mole of `CH_(3)COOH+0.35` mole of `CH_(3COOH=3.6xx10^(-4))`

Text Solution

Verified by Experts

`pH=-logK_(a)+log(([CH_(3)COO^(-)])/([CH_(3)COOH]))`
`:. pH=-log1.8xx10^(-5)+log((4.1xx60)/(82xx4))=4.74+log((3)/(2))=4.62`
`(b) pOH=-logK_(b)+log(([B^(+)])/([BOH]))`
`:.pOH=-log1.8xx10^(-5)+log((2.5)/(0.5))=4.74+log5=5.44`
`:.pH=14-pOH=8.56`
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Knowledge Check

  • Calculate pH of a solution of given mixture ( 0.1 "mol " CH_(3)COOH+0.2 mol CH_(3)COONa ) in 100 ml of mixture. K=2xx10^(-5) .

    A
    `4.6`
    B
    `5.6`
    C
    `6.6`
    D
    `7.6`

  • pH of a mixture which is 0. 1 M in CH_(3)COOH and 0.05 M in (CH_(3)COOH)_(2)Ba is [pK_(a) of CH_(3)COOH=4.74]

    A
    4.74
    B
    5.04
    C
    4.44
    D
    `7.00`

  • Calculate the pH of a solution containing 0.1 M CH_(3)COOH and 0.15 M CH_(3)COO^(-) . (K_(a) "of" CH_(3)COOH=1.8xx10^(-5))

    A
    9.1
    B
    3.9
    C
    10 .
    D
    4 .91