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Given the order of density: DiamondgtG...

Given the order of density:
Diamond`gt`Graphite`gt`Fullerence `C_(60)`, choose thye correct order for `C-C` bond length (Consider large bond length if there are two different bondlengths)

A

Diamond `lt` graphite`lt` fullerene `(C_(60))`

B

Diamond `gt` graphite`gt` fullerene `(C_(60))`

C

Diamond `gt` fullerene `(C_(90^(@))) gt`graphite

D

Diamond `lt` fullerene `(C_(90^(@))) lt`graphite

Text Solution

Verified by Experts

The correct Answer is:
C
Diamond -`sp^(3)` , no `pi`-bond character and `C-C` bond length=`154` pm
graphite -`sp^(2)`, aromatic and `pi` electrons are delocalised and `C-C` bond length =`141.5` pm
fullerene-`sp^(2)`, not so good delocalisation and there are two types of bond length. `C-C` bond length decreases as compared with diamond but is more than of graphite. Bond lengths are `143.5` pm and `138.3` pm.
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Knowledge Check

  • The correct order of C-O bond length among

    A
    `CO lt CO_(2) lt CO_(3)^(2-)`
    B
    `CO_(2) lt CO_(3)^(2-) lt CO`
    C
    `CO lt CO_(3)^(2-) lt CO_(2)`
    D
    `CO_(3)^(2-) lt CO_(2) lt CO`

  • Select the correct order of C-O bond length :

    A
    `Co gt Fe(CO)_(5)`
    B
    `[M(CO)_(4)(PF_(3))_(2)] lt [M(CO)_(5)(PF_(3))]`
    C
    `CO_(3)^(2-) lt CO`
    D
    `[V(CO)_(6)]^(-) gt [Ti(CO)_(6)]^(2-)`

  • Select the correct order of C-O bond length :

    A
    `Co gt Fe(CO)_(5)`
    B
    `[M(CO)_(4)(PF_(3))_(2)] lt [M(CO)_(5)(PF_(3))]`
    C
    `CO_(3)^(2-) lt CO`
    D
    `[V(CO)_(6)]^(-) gt [Ti(CO)_(6)]^(2-)`

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