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{:("List-1",,"List-II"),("(Amount of sub...

`{:("List-1",,"List-II"),("(Amount of substance)",,"(No. of moles of particular atoms in"),(,,"the given substance)"),("(P) " 6.022 xx 10^(24) " formula units of " Al_(2)(SO_(4))_(3).3H_(2)O,,"(1) 15 mole of O-atoms"),("(Q) 90 gm " C_(6)H_(12)O_(6),,"(2) 3 mole o-atoms"),("(R) 112 litre " SO_(3)(g) " at 1 atm and " 0^(@)C,,"(3) 2.5 mole O-atoms"),("(S) 54 gram " N_(2)O_(5)(g),,"(4) 150 mole O-atoms"):}`

A

`{:((P),(Q),(R),(S),),(4,2,1,3,):}`

B

`{:((P),(Q),(R),(S),),(4,2,3,1,):}`

C

`{:((P),(Q),(R),(S),),(4,1,2,3,):}`

D

`{:((P),(Q),(R),(S),),(2,1,4,3,):}`

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Find moles of O-atoms in 5.6 litres of SO_(3) at 0^(@)C ,1 atm ?

{:("Column I",,"Column II"),("(A) 3 moles of " Co(NH_(3))_(4)SO_(4),,"(P) 3 moles of S atom"),("(B) 1 mole " FeKCo(NO_(2))_(6),,"(Q) 1 mole Fe"),("(C) 1.5 moles" [Fe(H_(2)O)_(5)SCN]SO_(3),,"(R) 12 moles O atoms"),("(D) 0.75 moles " K_(2)Cu(SCN)_(4),,"(S) 6 moles N atoms"),(,,"(T) 1.5 moles K atoms"):}

Knowledge Check

  • {:(,"LIST -I",,"LIST -II"),((P),Fe_(2)(C_(2)O_(4))_(3) to Fe_(2)(SO_(4))_(3)+3CO_(2),(1),0.5 M = 5N),((Q),Mg(MnO_(4))_(2) to MgSO_(4)+2MnSO_(4),(2),"nf as oxidant is infinity "),((R),K_(2)Cr_(2)O_(7) to K_(2)CrO_(4),(3),"1 mole = 6 equivalent"),((S),H_(2)O_(2) to H_(2)O + 1/2 O_(2),(4),"nf is 2 for each half reaction "):}

    A
    `{:(P,Q,R,S),(4,3,2,1):}`
    B
    `{:(P,Q,R,S),(2,1,4,3):}`
    C
    `{:(P,Q,R,S),(3,2,1,4):}`
    D
    `{:(P,Q,R,S),(2,4,1,3):}`

  • In the reaction CrO_(5) + H_(2)SO_(4)rarr Cr_(2)(sO_(4))_(3)+H_(2)O+O_(2) , one mole of CrO_(5) will liberate how many molesof O_(2) :

    A
    `5//2`
    B
    `5//4`
    C
    `9//2`
    D
    `7//4`

  • In the reaction, 4NH_(3)(g)+5O_(2)(g) rarr 4NO(g)+6H_(2)O(g) , when 1 mole of ammonia and 1 mole of O_(2) are made to react to completion

    A
    (a)1.0 mole of H_(2)O is produced
    B
    (b)1.0 mole of NO will be produced
    C
    (c )All the oxygen will be consumed
    D
    (d)All the ammonia will be consumed

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