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20 mL of a gaseous hydrocarbon was explo...

20 mL of a gaseous hydrocarbon was exploded with 120 mL of oxygen . A contraction of 60 mL was observed and a further contraction of 60 mL took place when KOH was added. What is the formula of the hydrocarbon?

A

`C_(3)H_(6)`

B

`C_(3)H_(8)`

C

`C_(2)H_(6)`

D

`C_(4)H_(10)`

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Knowledge Check

  • 6 mL of a gaseous hydrocarbon was exploded with excess of oxygen and the product cooled. A contraction of 9 mL was observed. A further contraction of 12 mL was observed on treatment with aqueous KOH. The formula of hydrocarbon is

    A
    `CH_(4)`
    B
    `C_(2)H_(4)`
    C
    `C_(2)H_(6)`
    D
    `C_(2)H_(2)`

  • If V mL of a gaseous hydrocarbon after explosion with excess of oxygen showed a contraction of 2.5V mL and further contraction of 2V mL with potash. What will be the molecular formula of hydrocarbon?

    A
    `C_(2)H_(4)`
    B
    `C_(2)H_(6)`
    C
    `C_(2)H_(2)`
    D
    `C_(3)H_(8)`

  • 10 mL of a gaseous hydrocarbon require 30 mL of oxygen for complete combustion. The hydrocarbon is

    A
    `C_2 H_4`
    B
    `C_2 H_2`
    C
    `C_2 H_6`
    D
    `C_3 H_6`

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