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In the sum of first n terms of an A.P. i...

In the sum of first n terms of an A.P. is `cn^2`, then the sum of squares of these n terms is

A

`(n(4n^(2) -1)c^(2))/(6)`

B

`(n(4n^(2) + 1)c^(2))/(3)`

C

`(n(4n^(2) - 1)c^(2))/(3)`

D

`(n(4n^(2) + 1)c^(2))/(6)`

Text Solution

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The correct Answer is:
C
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