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How many mole of oxygen is required for complete combustion of `1` mole of Alkenen.

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Volume of hydrocarbon `=8c.c.`: Volume of `O_(2)=40c.c`
Formula No. `1, (8)/(40)=(2)/(3n+)` (For alkane)
`(1)/(5)=(2)/(3n+1)` or `3n+1=10` or `3n=10-1=9 , n=3`
The value of `n` comes in whole number from `1st` formula it means hydrocarbon
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ALLEN-ALKENE, ALKANE & ALKYNE -EXCERSISE-3
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