For what kinetic energy of a neutron will the associated de-Broglie wavelength be `5.6 xx 10^(-10)m` ?

Explanation

To find the kinetic energy of a neutron associated with a de-Broglie wavelength of \(5.6 \times 10^{-10} \, m\), we can use the de-Broglie wavelength formula and the relationship between kinetic energy and momentum. Here’s a step-by-step solution:

### Step 1: Write the de-Broglie wavelength formula
The de-Broglie wavelength (\(\lambda\)) is given by the formula:
\[ \lambda = \frac{h}{p} \]
where \(h\) is Planck's constant and \(p\) is the momentum.
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