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If P is the pressure and d is the densit...

If P is the pressure and d is the density of gas, then P and d are related as :

A

`P alpha 1"/"d`

B

`P alpha d`

C

`P alpha d^2`

D

`P alpha 1"/"d^2`

Text Solution

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The correct Answer is:
To solve the problem of how pressure (P) and density (d) of a gas are related, we can follow these steps: ### Step 1: Understand Boyle's Law Boyle's Law states that for a given mass of gas at constant temperature, the volume (V) of the gas is inversely proportional to the pressure (P). This can be expressed mathematically as: \[ V \propto \frac{1}{P} \] or \[ PV = k \] where \( k \) is a constant. **Hint:** Remember that Boyle's Law applies when temperature is constant and relates pressure and volume. ### Step 2: Relate Volume to Density The density (d) of a gas is defined as its mass (m) divided by its volume (V): \[ d = \frac{m}{V} \] From this equation, we can express volume in terms of density: \[ V = \frac{m}{d} \] **Hint:** Density is mass divided by volume; rearranging this gives you volume in terms of mass and density. ### Step 3: Substitute Volume in Boyle's Law Since we know from Boyle's Law that \( V \) is inversely proportional to \( P \), we can substitute the expression for volume from the density equation: \[ P \propto \frac{1}{V} \] Substituting \( V = \frac{m}{d} \) into this gives: \[ P \propto \frac{d}{m} \] This indicates that if the mass (m) is constant, pressure (P) is directly proportional to density (d). **Hint:** When you substitute the expression for volume, pay attention to how the relationships change. ### Step 4: Conclusion From the relationship derived, we conclude that pressure (P) is directly proportional to density (d) when mass is constant: \[ P \propto d \] Thus, if density increases, pressure also increases, assuming the mass of the gas does not change. **Hint:** Think about how changes in one variable affect the other when they are directly proportional. ### Final Answer Therefore, the correct relationship between pressure (P) and density (d) of a gas is: \[ P \propto d \]
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Knowledge Check

  • It P is the pressure and rho is the density of a gas, then P and rho are realted as :

    A
    `P prop rho`
    B
    `P prop rho^(2)`
    C
    `P prop 1//rho`
    D
    `P prop 1//rho^(2)`
  • If c_(p) and c_(v) are the principal specific heats of an ideal gas in cal/gm .^(@)C,rho is the density, P is the pressure and T is the temperature of the gas, then Mayer's relation is

    A
    `rho(c_(p)-c_(v))=(P)/(JT)`
    B
    `c_(p)-c_(v)=(dP)/(JT)`
    C
    `c_(p)-c_(v)=(JP)/(rhoT)`
    D
    `c_(p)-c_(v)=(JT)/(rho P)`
  • If P is the pressure of a gas and rho is its density , then find the dimension of velocity in terms of P and rho .

    A
    `P^(1//2) rho^(-1//2)`
    B
    `P^(1//2) rho^(1//2)`
    C
    `P^(-1//2) rho^(-1//2)`
    D
    `P^(-1//2) rho^(-1//2)`
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