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When metal X is treated with sodium hydr...

When metal X is treated with sodium hydroxide, a white precipitate (A) is obtained, which is soluble in excess of NaOH to give soluble complex (B). Compound (A) is soluble in dilute HCl to form compound (C). The compound (A) when heated strongly gives (D), which is used to extract metal. Identify (X), (A), (B), (C) and (D). Write suitable equations to support their identities.

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Knowledge Check

  • A metal M reacts with sodium hydroxide to give a white precipitate X which is soluble in excess of NaOH to give Y. Compound X is soluble in HCI to form a compound Z. Identify M.X,Y and Z M , X , Y, Z

    A
    `Si, SiO_(2), Na_(2)siO_(3), SiCI_(4)`
    B
    `AI, AiI(OH)_(3), NaMgO_(3), AICI_(3)`
    C
    `Mg, Mg(Oh)_(3), NaMgO_(3), MgCI_(2)`
    D
    `Ca, Ca(OH)_(2) , Na_(2) CO_(3), NaHCO_(3)`

  • When metal 'M' is treated with NaOH , a white gelatinous precipitate 'X' is obtained which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. Then metal 'M'

    A
    Zn
    B
    Ca
    C
    `Al`
    D
    `Fe`

  • When metal 'M' is treated with NaoH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is

    A
    Ca
    B
    Al
    C
    Fe
    D
    Zn