In Friedel - Crafts reaction, `AlCl_(3)` is an electrophile.

Answer

### Step-by-Step Solution

1. **Understanding Friedel-Crafts Reaction**:
The Friedel-Crafts reaction is a type of electrophilic aromatic substitution where an aromatic compound (like benzene) reacts with an alkyl halide (like CH3Cl) in the presence of a catalyst.

2. **Role of AlCl3**:
In this reaction, aluminum chloride (AlCl3) acts as a catalyst. It is classified as a Lewis acid because it can accept an electron pair.

3. **Formation of Electrophile**:
AlCl3 coordinates with the alkyl halide (e.g., CH3Cl). This coordination leads to the formation of a carbocation (CH3+) which is the actual electrophile that will react with the benzene.

4. **Mechanism of Reaction**:
- The benzene ring, being electron-rich, attacks the carbocation (CH3+).
- This results in the formation of a new carbon-carbon bond between the benzene and the methyl group.
- During this process, a hydrogen atom from the benzene is removed, forming HCl and an AlCl4- ion.

5. **Final Products**:
The final products of the reaction are toluene (the methylated benzene), HCl, and AlCl3 (which can regenerate in the reaction).

6. **Conclusion**:
The statement that "AlCl3 is an electrophile" is false. Instead, AlCl3 acts as a catalyst and facilitates the generation of the electrophile (the carbocation) from the alkyl halide.