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Show that time required for 99% completi...

Show that time required for `99%` completionis twice the time required for the completion of `90%` of reactions for a first order reaction.
The decomposition of hydrocarbon follow the equation
`K=(4.5xx10^(11)5^(-1))e^(-28000K//T)" Calculate Ea"`.

Text Solution

Verified by Experts

`"For first order reaction, t"=(2.303)/(R )log.(a_(0))/(a_(0))`
`rArr" "t_(99%)=2xxt_(90%)`
`k=Ae^(-Ea//RT)`
`(Ea)/(RT)=(28000)/(T )`
`E_(a)=28000xxR`
`=28000xx8.314`
`E_(a)=232.79" KJ mol"^(-1)`
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The decomposition of hydrocarbon follows the equation k=(4.5xx10^(11)s^(-1))e^(-28000K//T) Calculate E_(a) .

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Knowledge Check

  • The time of completion of 90% of a first order reaction is approximately

    A
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    B
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