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Determine the amount of CaCl(2) dissolv...

Determine the amount of `CaCl_(2)` dissolved in 2.5L at `27^(@)C` such that its osmotic pressure is 0.75 atm at `27^(@)C`. (i for `CaCl_(2) = 2.47`)

Text Solution

Verified by Experts

For `CaCl_(2) , " " i= 2.47`
`pi = iCRT`
`=i(n_(B))/(V) xx RT`
`0.75 = (2.47 xx n_(B) xx 0.082 xx 300)/(2.5)`
`n_(B) = (0.75 xx 2.5)/(2.47 xx 0.082 xx 300)`
`n_(B) = 0.0308` mol
Amount = `0.0308` mol `xx` 111 g `mol^(-1)`
`= 3.148` g
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