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The decomposition of hydrocarbon follow...

The decomposition of hydrocarbon follows the equation `k=(4.5xx10^(11)s^(-1))e^(-28000K//T)`
Calculate `E_(a)`.

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`K=(4.5xx10^11 s^(-1)) e^(-28000k//T)`
Comparing the equation with Arrhenius equation,
`K=Ae^(-Ea//RT)`
`-E_a/R=-28000` K
`E_a=28000xx8.314`
`=232192 J "mol"^(-1)`
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