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Solute 'X' dimerises in water to the ...

Solute 'X' dimerises in water to the extent of 80 % 2.5 g of 'X' in 100 g of water increases the boiling point by 0.3 `.^(@)C` . The molar mass of 'X' is `[ K_(b=0.52 " K gmol"^(-1))]`

A

65

B

26

C

13

D

52

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A non -volatile solute.'A' tetramerises in water to the extent of 80% .2.5 g of 'A' in 100 g of water .lower the freezing point by 0.3 ""^(@)C .The molar mass of Å in mol 4^(-1) is ( K_(T) For water =1.86 K kg mol^(-1) )

A certain substance A tetramerizes in water to the extent of 80% . A solution of 2.5 g of A in 100 g of water lowers the freezing point by 0.3^(@)C . The molar mass of A is a. 120 , b. 61 ,c. 60 ,d. 62

6 grams of a substance 'A' dissolved in 100 g of water freezes at - 0.93^(@)C . The molecular mass of 'A' is ( K_(f)=1.86 Km^(-1) ).

If 10.0 g of a non-electrolyte dissolved in 100 g of water lowers the freezing point of water by 1.86^(@)C , the molar mass of the non-electrolyte is ( K_(f)=1.86 Km^(-1) )

A solution of 1.25 g of 'P' in 50 g of water lowers freezing point by 0.3^(@) C . Molar mass of 'P' is 94. K_("(water)") = 1.86 K kg mol^(-1) . The degree of association of ‘P’in water is

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  • Solute 'X' dimerises in water to the extent of 80% . 2.5 g of 'X' in 100 g of water increases the boiling point by 0.3^@C . The molar mass of 'X' is [K_b = 0.52 K kg mol^(-1)]

    A
    65
    B
    13
    C
    26
    D
    52

  • Solute 'X' dimersis in water to the extent of 80%. 2.5g of 'X' in 100 g of water increases the boiling point by ~0.3^@C. The molar mass of 'X' is [K_b = 0.52 K kg mol^-1]

    A
    65
    B
    13
    C
    26
    D
    52

  • A non-volatile solute, 'A' tetramerises in water to the extent of 80% . 2.5 g of 'A' in 100 g of water, lowers the freezing point by 0.3^@C . The molar mass of A in g mol^(-1) is (K_f for water = 1.86 K kg mol^(-1) )

    A
    62
    B
    155
    C
    221
    D
    354
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