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The r.m.s. value of I = I(1) sin omega ...

The r.m.s. value of `I = I_(1) sin omega t + I_(2) cos omega t ` is

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An AC current is given by I = I_(1) sin omega t + I_(2) cos omega t A hot wire ammeter will give a reading :

If i_(1) = 3 sin omega t and i_(2) =6 cos omega t , then i_(3) is

Knowledge Check

  • If i_(1)=3 sin omega t and (i_2) = 4 cos omega t, then (i_3) is

    A
    `5 sin(omega t +53^(@))`
    B
    `5 sin(omega t +37^(@))`
    C
    `5 sin(omega t +45^(@))`
    D
    `5 sin(omega t +35^(@))`

  • An alternating voltage is given by: e = e_(1) sin omega t + e_(2) cos omega t . Then the root mean square value of voltage is given by:

    A
    `sqrt(e_(1)^(2) + e_(2)^(2))`
    B
    `sqrt(e_(1)e_(2))`
    C
    `sqrt((e_(1)e_(2))/(2))`
    D
    `sqrt((e_(1)^(2) e_(2)^(2))/(2))`

  • r.m.s. value of current i=3+4 sin (omega t+pi//3) is:

    A
    5A
    B
    `sqrt17A`
    C
    `(5)/(sqrt2)A`
    D
    `(7)/(sqrt2)A`

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